CV029 - Five Suspects

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Five Suspects
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Puzzle Number 029
Puzzle Name Five Suspects
Picarats Given 20 Picarats
Type Write Answer
Location Manor Parlor
Previous Puzzle CV028 - Find the Dot
Next Puzzle CV030 - One-Line Puzzle 1

This is the twenty-ninth puzzle that appears in Professor Layton and the Curious Village. To access this puzzle, you must talk to Inspector Chelmey. In order to solve this puzzle, you must determine how many suspects are telling the truth using their statements.

Contents

[edit] Hints

Hint One
    This puzzle might look like a big mess at first, but it's fairly simple when all is said and done.

    Take E, for example, who says everyone is lying. If she is actually telling the truth, then her statement becomes a lie, and she must be ruled out. Yep, E's a liar for sure.

Hint Two
    Let's rule out another couple of suspects. If A's statement is true, then three other people should be saying the same thing as A. This is not the case, so A is a liar.

    If B is telling the truth, two other suspects should say the same thing as B. Once again, this is not the case, so B must be lying.

Hint Three
    So, to sum things up, so far we've proven that A, B, and E are lying. Let's examine the last two suspects.

    If three people are lying, the other two suspects should have the same statement, but everyone is saying something different. On the other hand, if four of the five suspects are lying...


[edit] Messages

[edit] When Failed

Try again!

Try to think like a detective and look for inconsistencies between the statements.

[edit] When Completed

That's right!

Every suspect accused a different number of people. If anyone was telling the truth, it had to be one suspect, no more or less.

The only suspect whose statement fits that condition is D. It looks like he's a free man now.

[edit] Solution

Only one suspect is telling the truth.

[edit] Progress

925 Picarats and 56 Hint Coins.



Last edited by Squiggle on 25 December 2015 at 21:51
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