CV067 - How Many Sweets? (UK)

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For the puzzle appearing in the US version, see CV067 - The Chocolate Code (US)
How Many Sweets?
Puzzle Number 067
Puzzle Name How Many Sweets?
Picarats Given 40 Picarats
Type Write Answer
Location Clock Tower
Previous Puzzle CV066 - Birthday Girl (US)
CV066 - Five Borrowers (UK)
Next Puzzle CV068 - Find the Pentagons

This is the sixty-seventh puzzle that appears in the UK version of Professor Layton and the Curious Village. To access this puzzle, you must talk to Lucy. In order to solve this puzzle, you must determine how many sweets the three boys have between them.


[edit] Hints

Hint One
    If B gave C two sweets, everyone would have the same number.

    This must mean that the difference between A and B is two sweets, and the difference between B and C is twice that, making four.

Hint Two
    You know from Hint 1 that the difference between A and B is two sweets. You also know that if B got one sweet from C, he would have twice as many sweets as A.

    Put these two facts together and you should be able to work out how many sweets A has.

Hint Three
    You can work out from Hint 2 that A has three sweets.

    That makes it easy to work out how many B has, since you know he has two more!

[edit] Messages

[edit] When Failed

Too bad!

[edit] When Completed

That's right! There are nine sweets in total.

The difference between the number of sweets A and B have is two. If B had one more sweet, he would have twice and many as A. Therefore, A + 3 = 2A, which means A has three sweets. B must then have five, as he has one less than twice what A has. If C had two more sweets he would have the same as A, so he must have one.

[edit] Solution


The boys have nine sweets in total.

[edit] Progress

2385 Picarats and 119 Hint Coins.

Last edited by Squiggle on 30 December 2015 at 05:10
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