CV102 - Aces and the Joker

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Aces and the Joker
Puzzle Number 102
Puzzle Name Aces and the Joker
Picarats Given 40 Picarats
Type Write Answer
Location Tower Road
Previous Puzzle CV101 - Splitting It Up
Next Puzzle CV103 - Wood Cutouts

This is the one hundred and second puzzle that appears in Professor Layton and the Curious Village. To access this puzzle, you must talk to Martha. In order to solve this puzzle, you must determine the percentage chance that all four aces will be turned over before the joker is turned over.


[edit] Hints

Hint One
    Out of 53 cards, four are aces. Each time you flip a card, the probability of turning over an ace increases...but you really don't need to work out any of that.

    Think about what you can do to eliminate other variables to consider.

Hint Two
    If you distill this question down to its simplest form, it's just asking you how likely it is you'll flip over four aces in any order before you turn over the joker.

    The other 48 cards have nothing to do with the problem.

Hint Three
    OK, let's lay it all out on the table, so to speak.

    There are five cards that actually matter in this puzzle. Of those five, the joker has to come last. What's the probability of flipping the joker after the other four cards?

[edit] Messages

[edit] When Failed

Too bad.

Don't worry! You don't need to bother with complex calculations to solve this one!

[edit] When Completed

That's right!

While it may seem like you need to take other cards into account, no card in the deck, save the joker and four aces, plays any part in calculating the percentage.

Knowing that you only have to deal with five cards in your calculations, the rest is easy. You have five cards to flip, and you need one of the those five cards to be last. So your answer is one out of five, or 20 percent.

[edit] Solution


There is a 20% chance the joker will be flipped last.

[edit] Progress

2785 Picarats and 138 Hint Coins.

Last edited by Squiggle on 4 January 2016 at 20:36
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