CV118 - Red and Black Cards

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Red and Black Cards
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118B.gif
Puzzle Number 118
Puzzle Name Red and Black Cards
Picarats Given 50 Picarats
Type Write Answer
Location Town Hall
Previous Puzzle CV117 - Painting a Cube
Next Puzzle CV119 - Red and Blue 1

This is the one hundred and eighteenth puzzle that appears in Professor Layton and the Curious Village. To access this puzzle, you must examine the bottom of the rightmost window. In order to solve this puzzle, you must determine how many times out of 1,000 you can expect the number of red cards in one pile to match the number of black cards in the other pile.

Contents

[edit] Hints

Hint One
    How many red cards and black cards are there in a deck of 52 cards?

Hint Two
    There are a total of 26 black cards and 26 red cards in a 52-card deck.

Hint Three
    The number of red cards in pile A is equal to 26 minus the number of black cards in pile A.

    You can also reverse this statement and apply it to the black cards, so...


[edit] Messages

[edit] When Failed

Give it another shot.

[edit] When Completed

You can expect a corresponding number of red and black cards to show up between the piles 1,000 times out of 1,000 tries.

There are 26 cards of each color in a 52-card deck. If you form two piles of 26 randomly selected cards from this deck, the number of red cards in pile A is equal to 26 cards minus the number of black cards in pile A. In pile B, the situation is reversed. No matter how the cards are divided, the number of red cards in pile A will be equal to the number of black cards in pile B, and vice versa.

[edit] Solution

118ST.gif

The number of red and black cards would be the same 1,000 times.

[edit] Progress

480 Picarats and 37 Hint Coins.



Last edited by Squiggle on 6 January 2016 at 04:06
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