DB047 - The Mayoral Election

«  Odd Shape Out
The Mayoral Election
Who's Mr. Anderson? »

The Mayoral Election
Puzzle Number 047
Puzzle Name The Mayoral Election
Picarats Given 25 Picarats
Type Write Answer
Location Town Hall Plaza
Previous Puzzle DB046 - Odd Shape Out
Next Puzzle DB048 - Who's Mr. Anderson?

This is the forty-seventh puzzle you will encounter in Professor Layton and the Diabolical Box. To access this puzzle, you must examine the town hall's door. In order to solve this puzzle, you must determine the fewest number of votes that a candidate needs to secure a sure victory in the town election.


[edit] Hints

Hint One
    Think about how many votes exist in the town, excluding the three cast by the candidates themselves.

Hint Two
    Even the three candidates themselves have the right to vote.

    Of course, seeing as how each of them want to win, it's a given that the candidates will likely vote for themselves.

Hint Three
    Forty votes, minus the three votes cast by the candidates, leaves you with 37 votes.

    Find the number of votes it takes to gain a majority in a pool of 37 voters, and add one additional vote to that sum to get your answer.

[edit] Messages

[edit] When Failed

Too bad!

Think hard about the clues you've been given and try again.

[edit] When Completed

That's right!

The winner has to have at least 20 votes for a certain victory. Since each of the candidates dislikes the other two, each will likely vote for themselves. Forty votes minus those three votes leaves 37 votes. The winner will need over half the votes--in this case, a minimum of 19 additional votes. Add the winning candidate's personal vote and you get 20 votes. Even if another candidate gathered all the remaining 18 votes, it wouldn't be enough to overcome the candidate with 20 votes.

[edit] Solution


A candidate will need a minimum of 20 votes.

[edit] Progress

820 Picarats and 59 Hint Coins.

Last edited by Squiggle on 6 December 2015 at 03:55
This page has been accessed 266 times.