DB064 - Stones in a Vase

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Stones in a Vase
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Puzzle Number 064
Puzzle Name Stones in a Vase
Picarats Given 20 Picarats
Type Write Answer
Location Antique Shop
Previous Puzzle DB063 - Numbered Cards
Next Puzzle DB065 - The Ancient Map

This is the sixty-fourth puzzle you will encounter in Professor Layton and the Diabolical Box. To access this puzzle, you must talk to Dawson. In order to solve this puzzle, you must how many stones must be removed in order of gaining the best chance of removing an equal number of black and white stones.

Contents

[edit] Hints

Hint One
    Since the stones are of the same size and feel, there is absolutely no way to tell them apart while removing them.

Hint Two
    The best shot you'll have at pocketing those coins is just around 50 percent.

    There's no way of ensuring you'll win the coins.

Hint Three
    Let's think about this for a moment.

    Whether you pull out two stones or 100 stones, your chances of winning the gold are the same: just about 50 percent.


[edit] Messages

[edit] When Failed

Too bad!

In situations like this one, it pays to go for the big money, so don't hold back!

[edit] When Completed

Well done!

If you remove 100 stones from the vase, only one will remain inside. If that remaining stone is white, it means you've successfully removed 50 stones of each color. Of course, removing just two stones would give you the same chance of winning the coins as removing 100 stones, but the amount of money you receive for successfully removing 100 stones dwarfs the reward you'd receive for two stones.

[edit] Solution

100 stones must be removed from the vase.

[edit] Progress

2095 Picarats and 142 Hint Coins.



Last edited by Squiggle on 8 December 2015 at 05:15
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