DB109 - Walking the Dog

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Walking the Dog
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Walking the Dog
Puzzle Number 109
Puzzle Name Walking the Dog
Picarats Given 50 Picarats
Type Write Answer
Location West Y-Road
Previous Puzzle DB108 - The Knight's Tour 3
Next Puzzle DB110 - Chelmey's Route

This is the one hundred and ninth puzzle you will encounter in Professor Layton and the Diabolical Box. To access this puzzle, you must talk to Lila. In order to solve this puzzle, you must determine the distance the dog will run in feet between the father and the daughter before he catches up to the daughter.


[edit] Hints

Hint One
    Wordy problems like this one often have a trap buried somewhere in them. Don't get caught up in the wording.

    The dad walks at two feet per second, and the daughter walks at one foot per second, so for every second that passes, the distance between the two shrinks by one foot.

Hint Two
    The father sets out 10 seconds after his daughter. The daughter walks at a rate of one foot per second, so she's already 10 feet ahead of her father when he starts walking.

    Using what you've heard from this hint and the last one, you should now know that the father catches up to his daughter in 10 seconds.

Hint Three
    The dog runs at a rate of five feet per second.

    The father catches up to his daughter in exactly 10 seconds.

[edit] Messages

[edit] When Failed

Too bad!

Are you sure you aren't overthinking this one?

[edit] When Completed


The dog will have to run 50 feet in total.

According to the puzzle, the dog runs for the entire time it takes for the father to catch up with his daughter. Since the daughter has a 10 foot head start, and her dad gains on her at a rate of one foot per second, he'll catch up in 10 seconds. The dog is running at a rate of five feet per second, so the answer must be 50 feet.

[edit] Solution

The dog will run a total of 50 feet.

[edit] Progress

2770 Picarats and 160 Hint Coins.

Last edited by Squiggle today at 05:42
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