UF148 - Matchstick Math

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Matchstick Math
PL3148T.gif
PL3148B.png
Puzzle Number 148
Puzzle Name (US)Matchstick Math
(UK)Mathematchsticks
Picarats Given 25 Picarats
Type Write Answer
Location Azure Avenue
Previous Puzzle UF147 - Paving the Garden
Next Puzzle UF149 - Strange Symbols

This is the one hundred and forty eighth puzzle you will encounter in Professor Layton and the Unwound Future. To access this puzzle, you must examine the leftmost tree. In order to solve this puzzle, you must determine the fewest number of matchsticks that must be moved to make a valid equation.

Contents

[edit] Hints

Hint One
    Here's a Roman-numeral primer:
    I = 1, II = 2, and III = 3.

    IIII, however, does not equal four.

    IV = 4 and V = 5, so the I in front of the V means one less than five.

    VI = 6, VII = 7, and VIII = 8.

    IX = 9, X = 10, and XI =11.

Hint Two
    The answer should reveal itself if you understand Hint One and you're willing to look at things from various points of view.

Hint Three
    As mentioned in Hint Two, it's important to "look at things from various points of view." In other words, don't be afraid to turn this problem on its head...

Super Hint
    Flip the equation upside down.

    Well, would you look at that! You don't need to move any matches at all. The equation is completely valid as is!


[edit] Messages

[edit] When Failed

Too bad!

There's a twist here somewhere...

[edit] When Completed

You're on fire!

Zero matches is correct.

If you look at the equation upside down, it becomes 10 = 9 + 1 in Roman numerals.

The phrase "fewest number of matches" might have tricked you into thinking "at least one match," but "fewest" can mean no matches at all!

[edit] Solution

PL3148ST.png

Zero matches can be moved.

[edit] Progress

2330 Picarats and 186 Hint Coins.



Last edited by Squiggle on 27 November 2015 at 03:14
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