DB152 - The Card Tournament
« Colin's Score | |
The Diabolical Box » |
The Card Tournament | |
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Puzzle Number | 152 |
Puzzle Name | The Card Tournament |
Picarats Given | 80 Picarats |
Type | Write Answer |
Location | Layton's Challenges |
Previous Puzzle | DB151 - Colin's Score |
Next Puzzle | DB153 - The Diabolical Box |
This is the one hundred and fifty-second puzzle you will encounter in Professor Layton and the Diabolical Box. This puzzle can be accessed through Professor Layton's Challenges. In order to solve this puzzle, you must determine how many hands in round-robin Wallace played before leaving.
Contents |
[edit] Hints
[edit] Messages
[edit] When Failed
Too bad!
This is a calculation problem, but it does take some ingenuity to solve.
[edit] When Completed
Good job!
Wallace played four hands. First, you need to find the total number of hands if everyone stayed. You can find it with an equation like the one here. If there were 11 people, there would've been 55 matches, and if there were 12 people, there would've been 66. Since we know 59 hands were played, there must have been 12 people at the start. When we subtract the 59 hands played from the 66 ideal, we learn that Wallace missed seven hands. Since everyone would've played 11 hands ideally, that means Wallace only played four hands.
[edit] Solution
Wallace played four hands.
[edit] Progress
5401 Picarats and 230 Hint Coins.
Puzzles in Professor Layton and the Diabolical Box |
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